If an object travels from point A to B at 12 Kmph and from point B to A at 16 Kmph, what is the average speed?

I am looking for an answer other than (12+16)/2 = 14. I am not calculating velocity.


If an object travels from point A to B at 12 Kmph and from point B to A at 16 Kmph, what is the average speed?
Let distance between A and B = d km


Total distance = 2d km


Time taken in moving from A to B = d/12 h


Time taken in moving from B to A = d/16 h


Total time taken = d/12 h + d/16 h = d(1/12 + 1/16) h


Average speed = total distance/total time taken


= 2d/(d(1/12 + 1/16)) km/h


= 2/(1/12 + 1/16) km/h


= 2*16*12/(16 + 12) km/h


= 13.7 km/h


Ans: 13.7 km/hIf an object travels from point A to B at 12 Kmph and from point B to A at 16 Kmph, what is the average speed?
average speed= total distance /total time


now let us suppose distance between a and b is x km


then time taken for the forward journey= x/12


and that for the return journey is=x/16


since the total distance is 2x


so the avg speed= 2x/((x/12)+(x/16))=96/7


at the first go it would seem 14 though
Let the distance from A to B is x


now time taken to travel from A to B is x/16


now time taken to travel from B to A is x/12


total time taken=7x/48


total distance=2x


average speed=(2x)/7x/8=16/7=2.2857 km/hour(since x cancels)
the average speed IS 14 kmph though. velocity has a direction. why don't you do your own homework???

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