First calculate force.
F = a*m = 9.8*78 = 764.4 kg*m/s^2
Now calculate work.
W = Fd = 764.4 * 6 = 4586.4 kg*m^2/s^2
Convert units.
1 kg*m^2/s^2 = 1 joule, so
4586.4 kg*m^2/s^2 = 4586.4 jouleAn object with a mass of 78 kilograms is lifted through a height of 6 meters . How much work is done?
The force is
78*9.81 and the distance is 6 m
Work is F*d
for this case
work =78*9.81*6
j
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