What is the temperature an object can reach that will be the same in Celsius and in Fahrenheit ?

from ur question...


C=5/9(F-32)


C=F





answer.


F=5/9F-160/9


4/9F=-160/9


4F=-160


F= -40


the answer is -40What is the temperature an object can reach that will be the same in Celsius and in Fahrenheit ?
-40What is the temperature an object can reach that will be the same in Celsius and in Fahrenheit ?
hey its more of a quiz question %26amp; it has become very common





we generally use tis formula,and coz the temp is same in celcius as well as farenheit we can replace c by f or vice versa





(f-32) = 9c/5


f-32= 9f/5


-32= 9f/5 - 5f/5


-32= 4f/5


-32*(5/4)=f


-40=f
(f-32) = 9c/5


f-32= 9f/5


-32= 9f/5 - 5f/5


-32= 4f/5


-32*(5/4)=f


-40=f
-40
-40 C = -40 F
-40
The equation you listed is the relationship between a Fahrenheit temperature, represented by ';F,'; and the corresponding Celsius (or centigrade) temperature, ';C.';





C = 5(F-32)/9





We want to find the value where F and C are the same -- in other words, F=C. But since F=C, any place we see the C variable, we can replace it with (or ';substitute';) the F. That gives us:





F = 5(F-32)/9





Now we just have to solve this for F. We start by multiplying both sides by 9:





9F = 5(F-32)





Using the distributive property on the right-hand side,





9F = 5F - 160





Subtracting 5F from both sides gives





4F = -160





And, finally, we divide both sides by 4:





F = -40





And since C = F, C = -40, too.





Let's test our answer. The original equation was:





C = 5(F-32)/9





If we evaluate this equation when C = -40 and F = -40, do we get a true statement? Let's find out:





-40 = 5(-40-32)/9





We simplify inside the parentheses first: -40-32 = -72





-40 = 5(-72)/9





Next, 5*(-72) = -360





-40 = -360/9





And -360/9 = -40





-40 = -40





That's certainly a true statement, which means we found a correct solution.





Hope that helps!
-40