If an object is propelled straight upward from ground level with an initial velocity of 48?

its height ft per second, h in feet t seconds labor is given by the equation h=16t^2+48t After how many seconds is the height 32 ft?If an object is propelled straight upward from ground level with an initial velocity of 48?
Set h = 32, so 32 = 16t^2 + 48t. Solve this quadratic equation for t.





You can make the equation a little easier to work with by dividing both sides by 16.


32/16 = (16/16)t^2 + (48/16)t





2 = t^2 + 3t





However, that equation is incorrect. The correct equation is h = -16t^2 + 48





You'll get two answers. Both are correct. One is when the ball is on the way up, the other when it's on the way down.