An object with a mass of 78 kilograms is lifted through a height of 6 meters . How much work is done?

First calculate force.


F = a*m = 9.8*78 = 764.4 kg*m/s^2





Now calculate work.


W = Fd = 764.4 * 6 = 4586.4 kg*m^2/s^2





Convert units.


1 kg*m^2/s^2 = 1 joule, so


4586.4 kg*m^2/s^2 = 4586.4 jouleAn object with a mass of 78 kilograms is lifted through a height of 6 meters . How much work is done?
The force is


78*9.81 and the distance is 6 m


Work is F*d


for this case


work =78*9.81*6





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